sqrt(3x^2+12x+13)=2x+5

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Solution for sqrt(3x^2+12x+13)=2x+5 equation: 


Simplifying
sqrt(3x2 + 12x + 13) = 2x + 5

Reorder the terms:
qrst(13 + 12x + 3x2) = 2x + 5
(13 * qrst + 12x * qrst + 3x2 * qrst) = 2x + 5
(13qrst + 12qrstx + 3qrstx2) = 2x + 5

Reorder the terms:
13qrst + 12qrstx + 3qrstx2 = 5 + 2x

Solving
13qrst + 12qrstx + 3qrstx2 = 5 + 2x

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Reorder the terms:
-5 + 13qrst + 12qrstx + 3qrstx2 + -2x = 5 + 2x + -5 + -2x

Reorder the terms:
-5 + 13qrst + 12qrstx + 3qrstx2 + -2x = 5 + -5 + 2x + -2x

Combine like terms: 5 + -5 = 0
-5 + 13qrst + 12qrstx + 3qrstx2 + -2x = 0 + 2x + -2x
-5 + 13qrst + 12qrstx + 3qrstx2 + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
-5 + 13qrst + 12qrstx + 3qrstx2 + -2x = 0

The solution to this equation could not be determined.

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